100.debounce

Write a function named debounce that receives one parameter:

a function named callback

The debounce function should return a new function, let's name it debouncedCallback that will behave exactly like callback but it will only run when at least 1000ms have passed without it being invoked again.

Example 1

const printSum = (a, b) => {
  console.log(a + b);
}

const debouncedPrintSum = debounce(printSum);

debouncedPrintSum(1, 2);
debouncedPrintSum(11, 12);
debouncedPrintSum(100, 200);

/**
 * The number 300 should be printed to the console
 * after with a 1 second delay. That's because the
 * function is debounced so it only runs if it hasn't
 * been invoked for 1000ms. The first two calls are
 * thus ignored, and the last one will be executed.
 */

Example 2

const printSum = (a, b) => {
  console.log(a + b);
}

const debouncedPrintSum = debounce(printSum);

debouncedPrintSum(1, 2);
debouncedPrintSum(3, 4);
debouncedPrintSum(5, 6);

setTimeot(() => {
    debouncedPrintSum(7, 8);
    debouncedPrintSum(9, 10);
    debouncedPrintSum(11, 12);
}, 2000)

/**
 * Running the code above should:
 * 1. Print the number `11` after 1 second
 * 2. Print the number `23` after 3 more seconds
 * 
 * That's because the function is debounced
 * and the only invocations that actually run are:
 * - `debouncedPrintSum(100, 200);`
 * - `debouncedPrintSum(100, 200);`
 */